2x^2+5/2x-3/2=0

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Solution for 2x^2+5/2x-3/2=0 equation: 


x in (-oo:+oo)

2*x^2+(5/2)*x-(3/2) = 0

2*x^2+(5/2)*x-3/2 = 0

2*x^2+5/2*x-3/2 = 0

DELTA = (5/2)^2-(-3/2*2*4)

DELTA = 73/4

DELTA > 0

x = ((73/4)^(1/2)-5/2)/(2*2) or x = (-(73/4)^(1/2)-5/2)/(2*2)

x = ((73/4)^(1/2)-5/2)/4 or x = (-((73/4)^(1/2)+5/2))/4

x in { (-((73/4)^(1/2)+5/2))/4, ((73/4)^(1/2)-5/2)/4 }

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